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Last updated on July 16th, 2025

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Derivative of 1/e^x

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We use the derivative of 1/e^x, which is -1/e^x, as a measuring tool for how the function 1/e^x changes in response to a slight change in x. Derivatives help us calculate profit or loss in real-life situations. We will now talk about the derivative of 1/e^x in detail.

Derivative of 1/e^x for Canadian Students
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What is the Derivative of 1/e^x?

We now understand the derivative of 1/e^x. It is commonly represented as d/dx (1/e^x) or (1/e^x)', and its value is -1/e^x. The function 1/e^x has a clearly defined derivative, indicating it is differentiable within its domain.

 

The key concepts are mentioned below:

 

Exponential Function: (e^x) is the base of the natural logarithm.

 

Negative Exponent Rule: Used to simplify 1/e^x as e^-x.

 

Chain Rule: Rule for differentiating composite functions like e^-x.

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Derivative of 1/e^x Formula

The derivative of 1/e^x can be denoted as d/dx (1/e^x) or (1/e^x)'.

 

The formula we use to differentiate 1/e^x is: d/dx (1/e^x) = -1/e^x (or) (1/e^x)' = -1/e^x The formula applies to all x as e^x is always positive.

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Proofs of the Derivative of 1/e^x

We can derive the derivative of 1/e^x using proofs. To show this, we will use the rules of differentiation and exponent rules.

 

There are several methods we use to prove this, such as:

 

By First Principle Using Chain Rule We will now demonstrate that the differentiation of 1/e^x results in -1/e^x using the above-mentioned methods:

 

By First Principle The derivative of 1/e^x can be proved using the First Principle, which expresses the derivative as the limit of the difference quotient.

 

To find the derivative of 1/e^x using the first principle, consider f(x) = 1/e^x. Its derivative can be expressed as the following limit.

 

f'(x) = limₕ→₀ [f(x + h) - f(x)] / h Given that f(x) = 1/e^x, we write f(x + h) = 1/e^(x + h).

 

Substituting these into the equation, f'(x) = limₕ→₀ [1/e^(x + h) - 1/e^x] / h = limₕ→₀ [(e^x - e^(x + h)) / (e^(x + h) e^x)] / h = limₕ→₀ [-e^x(e^h - 1) / (e^(x + h) h)] = -1/e^x

 

Using Chain Rule To prove the differentiation of 1/e^x using the chain rule, We use the formula:

 

1/e^x = e^-x

 

The derivative of e^-x is found using the chain rule: d/dx (e^-x) = -e^-x

 

Therefore, d/dx (1/e^x) = -1/e^x

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Higher-Order Derivatives of 1/e^x

When a function is differentiated several times, the derivatives obtained are referred to as higher-order derivatives. Higher-order derivatives can be a little tricky.

 

To understand them better, think of a car where the speed changes (first derivative) and the rate at which the speed changes (second derivative) also changes. Higher-order derivatives make it easier to understand functions like 1/e^x.

 

For the first derivative of a function, we write f′(x), which indicates how the function changes or its slope at a certain point. The second derivative is derived from the first derivative, which is denoted using f′′(x).

 

Similarly, the third derivative, f′′′(x) is the result of the second derivative and this pattern continues.

For the nth Derivative of 1/e^x, we generally use f^n(x) for the nth derivative of a function f(x) which tells us the change in the rate of change (continuing for higher-order derivatives).

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Special Cases:

The function 1/e^x has no undefined points as e^x is never zero. When x is 0, the derivative of 1/e^x = -1/e^0, which is -1.

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Common Mistakes and How to Avoid Them in Derivatives of 1/e^x

Students frequently make mistakes when differentiating 1/e^x. These mistakes can be resolved by understanding the proper solutions. Here are a few common mistakes and ways to solve them:

Mistake 1

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Not simplifying the equation

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Students may forget to simplify the equation, which can lead to incomplete or incorrect results. They often skip steps and directly arrive at the result, especially when solving using the chain rule. Ensure that each step is written in order. Students might think it is unnecessary, but it is important to avoid errors in the process.

Mistake 2

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Incorrect use of Chain Rule

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While differentiating functions such as 1/e^(2x), students misapply the chain rule. For example: Incorrect differentiation: d/dx (1/e^(2x)) = 2(-1/e^(2x)). Correct differentiation: d/dx (1/e^(2x)) = -2/e^(2x). To avoid this mistake, ensure that the derivative of the exponent is correctly applied.

Mistake 3

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Not writing Constants and Coefficients

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There is a common mistake that students at times forget to multiply the constants placed before 1/e^x. For example, they incorrectly write d/dx (5/e^x) = -1/e^x. Students should check the constants in the terms and ensure they are multiplied properly. For example, the correct equation is d/dx (5/e^x) = -5/e^x.

Mistake 4

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Not Applying the Exponent Rules

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Students often forget to use the exponent rules. This happens when the negative exponent is not considered. For example: Incorrect: d/dx (e^-x) = e^-x. To fix this error, students should remember that the derivative of e^-x is -e^-x.

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Examples Using the Derivative of 1/e^x

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Problem 1

Calculate the derivative of (1/e^x · e^x)

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Here, we have f(x) = (1/e^x) · e^x.

 

Since 1/e^x · e^x = 1, the derivative is straightforward. f'(x) = d/dx (1) = 0.

 

Thus, the derivative of the specified function is 0.

Explanation

We find the derivative of the given function by realizing that 1/e^x · e^x simplifies to 1. The derivative of a constant, such as 1, is always 0.

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Problem 2

A chemical reaction decreases in concentration following the function C(x) = 1/e^x. Find the rate of change of concentration at x = 2.

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We have C(x) = 1/e^x.

 

Now, we will differentiate the equation: dC/dx = -1/e^x. Given x = 2, dC/dx = -1/e^2.

 

Therefore, the rate of change of concentration at x = 2 is -1/e^2.

Explanation

We find the rate of change of concentration at x = 2, which indicates how the concentration decreases at that point.

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Problem 3

Derive the second derivative of the function y = 1/e^x.

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The first step is to find the first derivative, dy/dx = -1/e^x.

 

Now we will differentiate again to get the second derivative: d²y/dx² = d/dx [-1/e^x] = 1/e^x.

 

Therefore, the second derivative of the function y = 1/e^x is 1/e^x.

Explanation

We use the step-by-step process, where we start with the first derivative. Differentiating again, we find the second derivative.

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Problem 4

Prove: d/dx (1/e^(2x)) = -2/e^(2x).

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Let’s start using the chain rule: Consider y = 1/e^(2x) = e^(-2x).

 

To differentiate, we use the chain rule, dy/dx = -2e^(-2x).

 

Substituting y = 1/e^(2x), d/dx (1/e^(2x)) = -2/e^(2x).

 

Hence proved.

Explanation

In this step-by-step process, we used the chain rule to differentiate the equation by considering the negative exponent. As a final step, we show how the result aligns with the original function.

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Problem 5

Solve: d/dx (1/e^x - x)

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To differentiate the function, we differentiate each term separately: d/dx (1/e^x - x) = d/dx (1/e^x) - d/dx (x) = -1/e^x - 1.

 

Therefore, d/dx (1/e^x - x) = -1/e^x - 1.

Explanation

In this process, we differentiate each term in the function separately to find the final derivative.

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FAQs on the Derivative of 1/e^x

1.Find the derivative of 1/e^x.

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2.Can we use the derivative of 1/e^x in real life?

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3.Is it possible to take the derivative of 1/e^x at any point?

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4.What rule is used to differentiate 1/e^x?

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5.Are the derivatives of 1/e^x and e^-x the same?

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Important Glossaries for the Derivative of 1/e^x

  • Derivative: The derivative of a function indicates how the given function changes in response to a slight change in x.

 

  • Exponential Function: A mathematical function of the form e^x, where e is the base of natural logarithms.

 

  • Chain Rule: A fundamental rule in calculus used to differentiate composite functions.

 

  • Negative Exponent: A mathematical operation that represents reciprocal powers, such as 1/e^x being e^-x.

 

  • Rate of Change: A measure of how a quantity changes concerning another variable, often time.
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Jaskaran Singh Saluja

About the Author

Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.

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Fun Fact

: He loves to play the quiz with kids through algebra to make kids love it.

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